63p^2-112=0

Solution for 63p^2-112=0 equation:

63p^2-112=0

a = 63; b = 0; c = -112;
Δ = b2-4ac
Δ = 02-4·63·(-112)
Δ = 28224
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{28224}=168$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-168}{2*63}=\frac{-168}{126}
=-1+1/3
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+168}{2*63}=\frac{168}{126}
=1+1/3
$